Come on guys...
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Jesse, that’s not how probability fucking works.
Gosh it’s almost like I was joking by coming to a correct conclusion through faulty reasoning
I mean I could have just been a complete dweeb and explain that the outcome of the second roll is unaffected by the outcome of the first, and you are just as likely to roll two ones in a row as you are to roll any two numbers, but then I’d have to find a locker to shove myself in
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I have a character that started with 14 12 10 8 4 3. In 2011.
He is my only character that hasn’t been downed, and he is religiously restricted suicidal. He is a Life Cleric and HUGELY beneficial to the party; magically, politically, & financially.
He is a 910 year old dwarf who has a guaranteed place in Elysium*. He just cant die of old age. He’s DESPERATE to die in combat.
*Terms and conditions apply.
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The trick is to say “this is just a practice roll” where the die can hear you, but wink at the GM so they know it’s the real roll. That way, the die will be a spiteful little punk and throw out the nat20 for the “practice”.
But don’t do that too often, or the die will figure out the trick.
And when the Nat 1 shows up, rub your eye because you had sand in it.
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Weirdly enough, it’s just the way probability works.
Once something stops being a possibility, and becomes a fact (ie. dice are rolled, numbers known) - future probability is no longer affected (assuming independent events like die rolls).
e.g. you have a 1/400 chance of rolling two 1s on a D20 back-to-back. But if your first roll is a 1, you’re back down to the standard 1/20 chance of doing it again - because one of the conditions has already been met.
That’s very interesting to me (I am a bit mathematically illiterate when it comes to probability). Wouldn’t it still have a lower chance of being a 1 if you said you want your second roll to be the one that counts beforehand? Or would different permutations screw with the odds, say rolling a 12 then a 1, rolling a 15 and a 1, etc, counting towards unfavourable possibilities and bringing it back to 1/20?
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That’s very interesting to me (I am a bit mathematically illiterate when it comes to probability). Wouldn’t it still have a lower chance of being a 1 if you said you want your second roll to be the one that counts beforehand? Or would different permutations screw with the odds, say rolling a 12 then a 1, rolling a 15 and a 1, etc, counting towards unfavourable possibilities and bringing it back to 1/20?
Because the outcome of a dice roll is an independent event (ie. the outcome of any given event does not impact subsequent events), it doesn’t matter if you said only your 2nd/3rd/4th etc. roll counted. Every roll has a 1/20 chance of rolling a 1 on a D20 die.
Consider this thought experiment, there are ~60.5m people, each rolling a 6-sided die. Only the people who roll a 6 can continue to the next round, and the game continues until there is only 1 winner.
After the first roll, only ~10m people remain in the game. After the second roll, ~1.7m people remain After the third roll, ~280K After the fourth, ~46.5K 5th, ~7.8K 6th, ~1.3K 7th, ~216 8th, ~36 9th, ~6 After the 10th and final roll, there should only be ~1 player remaining.
So even though initially there is only a 1-in-65m chance of rolling 10 6s back-to-back initially, each attempt still has a 1/6 chance of succeeding. By the time we get down to the final six contestants, they have each rolled a 6 nine times in a row - yet their chances of rolling it another time is still 1/6.
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The thing you’re getting by switching is the benefit of the information provided by the person who revealed an empty door.
Before a door is open, you have a 1/3 chance of selecting correctly.
After you select a door, the host picks from the other two doors. This provides extra information you didn’t have during your initial selection. The host points to a door they know is a dud and asks for it to open. So now you’re left with the question “Did I pick the correct door on the first go? Or did the host skip the door that had the prize?” There’s a 1/3 chance you picked the right door initially and a 2/3 chance the host had to avoid the prize-door.
Yeah I think the easiest way of understanding how monty affects the choice is to imagine 100 doors, and after you pick one monty opens 97 other ones. Wouldn’t you want to change after that?
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Me every time I think about this.
The die has no memory of its past roles
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That’s stupid. But obviously how the dice strikes the table impacts its balance and therefore the probability of rolling specific numbers. So we must figure out what side need to strike the table first to decrease the probability of getting an undesirable roll. Boom, I out physicsed you’re probabilities.
I did this with d6. I am a master at rolling low, cursed you may say but if I pick up a 1 the chance of rolling another one is lower. Or at least in my mind and memory.
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Right but the way I took the meme was that you would roll until you get a 1, then deciding the next roll is the “real” one.
brian@lemmy.ca The die doesn’t know it just rolled a 1. History doesn’t matter to it.
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Yeah I think the easiest way of understanding how monty affects the choice is to imagine 100 doors, and after you pick one monty opens 97 other ones. Wouldn’t you want to change after that?
tigeruppercut@lemmy.zip I interviewed someone for a jr data analyst roll once, and one of the questions I asked was to explain the Monty Hall problem.
They told me the odds were 50:50, so I rolled out the 100 door version.
They told me the odds were 50:50.
Management decided to hire him, anyway.
